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x^2(2x+3)=2x(3x^2+5x)
We move all terms to the left:
x^2(2x+3)-(2x(3x^2+5x))=0
We calculate terms in parentheses: -(2x(3x^2+5x)), so:
2x(3x^2+5x)
We multiply parentheses
6x^3+10x^2
We do not support expression: x^3
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